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Goryan [66]
2 years ago
13

A teacher asks five different students to write an equation with a solution of x = 4. The students and their equations are shown

below.
Student Adrian Bert Camille Daniel Etsuko Equation 2x + 6 = 2 2x-9 = -1 - 2x + 12 = 4 2(x + 2) = 10 2(x - 10) = -12

Which of the following students correctly wrote an equation with x = 4 as the solution? Select three that apply.

A. Bert
B. Daniel
C. Etsuko
D. Adrian
E. Camille​
Mathematics
1 answer:
tankabanditka [31]2 years ago
6 0

Answer:

I'm assuming the order corresponds the student to the equation. Because of this, the answer is simple:

Bert, Etsuko, and Camille.

Step-by-step explanation:

2x-9=-1, 2x=8, x=4

2(x-10)=-12, x-10=-6, x=4

-2x+12=4, -2x=-8, x=4

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What is 2logx−logy+2logz written as a single logarithm? log(xz)^2/y log2x/2yz logx^2y/z^2 logx^2/yz^2
Klio2033 [76]

Answer: \log\dfrac{x^2z^2}{y}

Step-by-step explanation:

Properties of logarithm:

(i)\ \ n\log a = a^n\\\\ (ii)\ \ \log m +\log n =\log (mn)\\\\ (iii)\ \ \log m-\log n =\log\dfrac{m}{n}

Consider,

2\log x-\log y+2 \log z\\\\ =\log x^2-\log y+\log z^2\ \ \ \ \text{[By (i)]}\\\\= \log x^2+\log z^2-\log y\\\\=\log(x^2z^2)-\log y\ \ \ \ [\text{By } (ii) ]\\\\=\log(\dfrac{x^2z^2}{y})    \ \ \ \ [\text{By (iii)}]

3 0
3 years ago
What number is it that, when multiplied by 18,27,36,45,54,63,72,81, or 99, gives a product in which the first and last figures a
allsm [11]

The given multipliers are factors of 9, the possible number will have 1 as first and last digit which gives the number as 101

<h3>How can the correct number be found?</h3>

The given numbers are;

18, 27, 36, 45, 54, 63, 72, 81, 99

Given that the first and the last figures are those of the multipliers, we have;

The first and last and last digit of the number can be 1, which gives;

Possible numbers includes; 11 and 101

By trying the possible numbers, the difference found is presented as follows;

99 × 11 = 1089 (The first and the last digit are not the same as the multiplier)

  • 99 × 101 = 9999 (First and last digit are not the same as the multiplier)

90 × 11 = 990

90 × 101 = 9090

The correct option is therefore 101

  • The number is 101

Learn more about multiplication of numbers here:

brainly.com/question/83239

#SPJ1

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Korolek [52]
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2 years ago
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morpeh [17]
Question plz thxs 
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