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3 years ago

Plz help with this I don’t know what to do

Mathematics

2 answers:

WITCHER [35]3 years ago

8 0

Answers:

Row One: 9, 15
Row Two: 8, 16, 20

Input the numbers only in each box. So that means you won't type in a comma.

The least common denominator is <u>12</u>

=======================================================

Explanation:

Your teacher wants you to list the multiples of each denominator.

The multiples of 3 are: 3, 6, 9, 12, 15
The multiples of 4 are: 4, 8, 12, 16, 20

The values in bold are what will go in the boxes in those first two rows.

The least common denominator is 12 because it is the smallest thing found in common in the two lists above. In other words, 12 is the LCM (least common multiple) of 3 and 4. Note how 3*4 = 12. This works because 3 and 4 do not have any common factors between them other than 1.

The LCD (least common denominator) is the LCM of the denominators. The LCD is useful for when you want to add or subtract fractions. The denominators must be the same for you be able to add or subtract them.

kozerog [31]3 years ago

3 0

Answer:

Just guessing here but would the bottom be 4,8,12,16,20 maybe since it is going by 4 then you do the same for the top since it is going by 3

Step-by-step explanation:

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An isosceles right triangle has a hypotenuse of length e. Select all that are true for the triangle.

____ [38]

<h3>2 Answers: </h3>

Choice C) Leg length = $\frac{e\sqrt{2}}{2}$
Choice E) Area = $\frac{e^2}{4}$

Note: if the formulas don't load properly, then you may need to refresh the page.

======================================================

Explanation:

For any 45-45-90 right triangle, the hypotenuse H is always sqrt(2) times the leg L

In terms of symbols, we can say

$H = L*\sqrt{2}$

We're told the hypotenuse is e, so H = e

Let's solve for L in terms of e

$H = L*\sqrt{2}\\\\e = L*\sqrt{2}\\\\L*\sqrt{2} = e\\\\L = \frac{e}{\sqrt{2}}\\\\$

Now let's multiply top and bottom by $\sqrt{2}$ to rationalize the denominator

$L = \frac{e}{\sqrt{2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{2}*\sqrt{2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{2*2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{4}}\\\\L = \frac{e\sqrt{2}}{2}\\\\$

If the hypotenuse is e, then the length of each leg is $\frac{e\sqrt{2}}{2}$

This matches with choice C, which is one of the two answers. This allows us to rule out choices A and B, as those expressions are not equivalent to the expression for choice C.

----------------

The two legs of any right triangle form the base and height. The order doesn't matter. The base is always perpendicular to the height. In a right triangle, the two legs are always perpendicular.

The base and height are $\frac{e\sqrt{2}}{2}$ each.

The area of the triangle is...

$\text{Area} = \frac{1}{2}*\text{base}*\text{height}\\\\\text{Area} = \frac{1}{2}*\frac{e\sqrt{2}}{2}*\frac{e\sqrt{2}}{2}\\\\\text{Area} = \frac{e\sqrt{2}*e\sqrt{2}}{2*2*2}\\\\\text{Area} = \frac{e*e\sqrt{2*2}}{2*2*2}\\\\\text{Area} = \frac{e^2\sqrt{4}}{2*2*2}\\\\\text{Area} = \frac{e^2*2}{2*2*2}\\\\\text{Area} = \frac{e^2}{2*2}\\\\\text{Area} = \frac{e^2}{4}\\\\$

This matches with choice E, which is the other answer. Choices D and F are eliminated as they are not equivalent to the expression for choice E.

4 0

3 years ago

Which equation represents the transformed function below?

german

Options would be nice, but the dotted line equation appears to be:
log(x) + 5,
A transformation of
log(x) , which is the equation for the solid line.

3 0

3 years ago

Read 2 more answers

Probability and Statistics

Rainbow [258]

Answer:

Step-by-step explanation: if you want to obtain the probability that x<em> </em> $\leq$ -3 , then you need to add the probability for the cases x=-3 and x=-5.

p=0.13+0.17= 0.3

answer=0.3

6 0

3 years ago

The ratio of the side length of Square A to the side length of Square B is 4:9. The side length of Square A is 12 yards. What is

lubasha [3.4K]

A/B : 4/9 = 12/B
cross multiply
(4)(B) = (9)(12)
4B = 108
B = 108/4
B = 27

P = 4a...where a is the length of one side
P = 4(27)
P = 108 yds <=== perimeter of square B

4 0

3 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

4 years ago