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Mnenie [13.5K]
4 years ago
10

Plz help!!!!!!!!!!!!

Mathematics
2 answers:
creativ13 [48]4 years ago
7 0

Answer:   \bold{x^{\frac{1}{3}}}

<u>Step-by-step explanation:</u>

\sqrt[6]{x^2} =x^{\frac{2}{6}}=x^{\frac{1}{3}}

muminat4 years ago
5 0
That seem to be right
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If there are 250 boy scouts from a region going on a camping trip and each tent can hold 8 scouts, how many tents are needed?
Sonbull [250]

Answer: 32 tents

Step-by-step explanation: 250÷ 8= 31.25 so you have to round that tent up because you can't just have a quarter of a tent. So 5 makes the 2 go up and it becomes 32

3 0
2 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
3 years ago
Plz help me with this question
Contact [7]

Answer: KJ becuase it is the first two like on but put backwards.

7 0
3 years ago
Read 2 more answers
-7a^3 + (-2a^3) I need to simplify
KengaRu [80]
If ^ means exponents, it should be -9a^6
4 0
3 years ago
Read 2 more answers
Select all of the situations which can be represented by the expression 25.75x + 10
gizmo_the_mogwai [7]

Answer:

Max has $10.00. He earns $25.75 for every lawn that he mows.

Sasha sells a scarf for $10.00 and x jackets for $25.75 each.

Step-by-step explanation:

8 0
3 years ago
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