Josephine solved a quadratic equation. Her work is shown below.
1 answer:
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Perimeter of quadrilateral ANCM = AN+NC+CM+MA
CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.
Perimeter (P) = 4x in
Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in
Therefore, P=4*20.5 = 82 in
CM=AM = x in
Therefore, AN=NC = x in
In other words, all sides of the new quadrilateral are equal.
Perimeter (P) = 4x in
Now, Cos 45 = (x-6)/x =>0.7041 = (x-6)/x => 0.7041x=x-6 =>x= 6/(1-0.70741)
x= 20.5 in
Therefore, P=4*20.5 = 82 in