Question

Pls helptitle=" {5}^{2x + 1} \div 25 = 125" alt=" {5}^{2x + 1} \div 25 = 125" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

${5}^{2x + 1} \div 25 = 125$

${5}^{2x + 1} \div 5² = 5³$

doing crisscrossed multiplication

${5}^{2x + 1}=5³×5²$

In multiplication common numbers is added

${5}^{2x + 1}=5^{3+2}$

If there is a same term than it can be add ,subtract .

;.

2x+1=5

2x=5-1

x=$4\div 2$

x=2 is a required answer.

Answer 2

I hope this answers it