Answer:
If the amplitude of motion is doubled, so the mass swings 8 cm to one side and then the other, the period of the motion will be <u>2 s</u>.
Explanation:
As we know that time period of the motion of the simple pendulum is given as
here we know that
L = length of the pendulum
g = acceleration due to gravity
so as per above formula we know that time period of the pendulum is independent of the amplitude of the motion of the time period
So we will say that there is no change in the time period of the motion when we increase the amplitude of the motion of the given pendulum
Answer:
F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^
the correct answer is "b"
Explanation:
The magnetic force is
F = i l x B
The bold are vectors, in this case they give us the direction of the current and the magnetic field, for which we can solve as a determinant
resolver
F = i ^ (4 12 - 0) + j ^ (0- 3 12) + k ^ (3 5 - 0)
F = i (48 i ^ - 36 j ^ + 15 k⁾
in this case i is the value of the current flowing through the cable
i = 16 mA = 0.016 A
F = 0.768 i ^ - 0.576 j ^ + 0.24 k ^
When reviewing the different answers, the correct answer is "b"
Answer:
Explanation:
The minimum height of a space shuttle from the surface of the earth is 304 kilometers.
So according to this data we calculate the value to g at that height.
We have the formula:
where:
g' = the acceleration due to gravity at the given height 'h' above the earth
R = radius of the earth
g = the acceleration due to gravity at the surface of the earth
Now, using eq. (1)