Using the kinematic equation below we can determine the distance traveled if t=2, a=7.4m/s^2. First we must determine the final velocity:
Now we will determine the distance traveled:
Therefore, the drag racer traveled 81.83 meters in 2 seconds.
Answer:
The answer is 50 Nm
Explanation:
<h3><u>Given</u>;</h3>
- Applied Force = 50 Newton
- Total Displacement = 1 meter
<h3>
<u>To </u><u>Find</u>;</h3>
Here,
W = F • d
W = 50 • 1
W = 50 Nm
Thus, Work done is 50 Nm
<u>-TheUnknownScientist 72</u>
False, although they are usually a liquid. Solvents can be a solid or gas as well. Also, solutes can be in any state as well.
The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy <em>PE</em> :
<em>PE</em> = <em>m g h</em>
<em>PE</em> = (2.0 kg) (9.8 m/s²) (3.0 m)
<em>PE</em> = 58.8 J
Energy is conserved throughout the block's descent, so that <em>PE</em> at the top of the curve is equal to kinetic energy <em>KE</em> at the bottom. Solve for the velocity <em>v</em> :
<em>PE</em> = <em>KE</em>
58.8 J = 1/2 <em>m v</em> ²
117.6 J = (2.0 kg) <em>v</em> ²
<em>v</em> = √((117.6 J) / (2.0 kg))
<em>v</em> ≈ 7.668 m/s ≈ 7.7 m/s
Answer:
linear charge density = -9.495 × 
C/m
Explanation:
given data
revolutions per second = 1.80 × 
radius = 1.20 cm
solution
we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force
so
- q × E = m × w² × r ..................1
- 9 × 
× 
q = m × w² × r ............2
and w = 
w = 
w = 1.80 × × 
w = 11304000 rad/s
so here from equation 2
- 9 × × 
1.80 × = 1.672 × 
× 11304000² × 0.0120
linear charge density = -9.495 × C/m
