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romanna [79]
3 years ago
13

Find the value of x.

Mathematics
2 answers:
EleoNora [17]3 years ago
8 0

\huge\bold{Given :}

Angle AOD = x - 10°

Angle DOC = 3x + 25°

Angle BOC = x + 5°

\huge\bold{To\:find :}

The value of x.

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\sf\purple{The\:value\:of\:x\:is\:32°}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

We know that,

\sf\pink{Sum\:of\:angles\:on\:a\:straight\:line\:=\:180°}

➪ ∠ AOD + ∠ DOC + ∠ BOC = 180°

➪ x - 10° + 3x + 25° + x + 5° = 180°

Combining like terms, we have

➪ 5x + 20° = 180°

➪ 5x = 180° - 20°

➪ 5x = 160°

➪ x = \frac{160}{5}

➪ x = 32°

Therefore, the value of x is 32°.

Now,

I) ∠ AOD = x - 10° = 32° - 10° = 22°

2) ∠ DOC = 3x + 25° = 3 x 32° +25° = 96° + 25° = 121°

3) ∠ BOC = x + 5° = 32° + 5° = 37°

\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}

∠ AOD + ∠ DOC + ∠ BOC = 180°

✒ 22° + 121° + 37° = 180°

✒ 180° = 180°

✒ L. H. S. = R. H. S.

\boxed{Hence\:verified.}

\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♡}}}}}

Sergeu [11.5K]3 years ago
3 0

\blue{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}}

Find the value of x.

\orange{\underline{\huge{\bold{\textit{\green{\bf{FORMULA}}}}}}}

SUM OF ANGLES ON STRAIGHT LINE = 180°

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

ANGLES\: R :-( x - 10)°,(3x + 25)°,(x + 5)°, \\  \\ ( x - 10)° + (3x + 25)° + (x + 5)° = 180 \\ 5x + 20 = 180 \\ 5x = 160 \\ x =  \frac{160}{5}  \\ x = 32° \\

\red{ANGLES R :-} \\  \pink{( x - 10)° = 32 - 10 = 22°} \\ \blue{ (3x + 25)°  = 32 \times 3 + 25 = 96 + 25 = 121°}\\  \orange{(x + 5)° = 32 + 5 = 37°}

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