25 Points! Please tell me how to answer this.

Please help me I'm stuck!!! on these problems

vitfil [10]

The answer for the last one is-36

4 0

3 years ago

Yoooooooooooooooooooooooooo can you please help me!?

klemol [59]

She has totally 10+5+3=18 marbles, so the probability is 10/18=5/9. The complement is (9-5)/9=4/9.

Hope this helped!

4 0

3 years ago

nicole is flying two kites. she has 104 feet of string out to one kite and 110 feet out to the other kite. the angle formed by t

tankabanditka [31]

Answer:

Step-by-step explanation:

Answer:

48.49 feet

Step-by-step explanation:

The diagrammatic sketch of the details given in the question was attached in the picture below.

From the picture below, the distance between the two kites is represented by (c) and can be calculated by using the cosine angle rule which is illustrated as:

$c^2 = a^2 + b^2 -2ab cos \ C$

where;

a = 110

b = 104

Cos C = 26°

Then;

$c^2 = 110^2 + 104^2 -2(110)(104) cos \ 26 \\ \\ c^2 = 12100 + 10816- 22880 ( 0.8988) \\ \\ c^2 = 22916- 20564.544 \\ \\ c^2 = 2351.456 \\ \\ c= \sqrt{2351.456} \\ \\ \mathbf{ c = 48.49 \ feet}$

8 0

3 years ago

Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.

barxatty [35]

Answer:

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

$\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx$

If $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ , $a = 0$ , $b = b$ and $\bar f = 8$ , then:

$\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8$

$\frac{7}{b}\int\limits^b_0 \, dx + \frac{10}{b} \int\limits^b_0 {x}\, dx - \frac{9}{b} \int\limits^b_0 {x^{2}}\, dx = 8$

$\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8$

$7 + 5\cdot b - 3\cdot b^{2} = 8$

$3\cdot b^{2}-5\cdot b +1 = 0$

The roots of this polynomial are determined by the Quadratic Formula:

$b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

7 0

3 years ago

Hi can someone help me on this please? I am having trouble understanding this one :) thx

fomenos

Answer:

I would say its the bottom one

Step-by-step explanation:

The top one goes to five while the bottom only goes to four, plus you cant have a negative amount of people you can only have from 0 to infinity amount of people.

4 0

3 years ago

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