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3 years ago

The data set shows the numbers of yogurt pretzels in various bags.

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

Answer:

The answer should be C

Step-by-step explanation

I've had this problem before, and know it should most definitely be C.

Hope I helped!

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Solve for n. n + 1 = 4(n - 8) n = 1 T n = 8 n = 11 n = 16

Komok [63]

Answer:

n=11

Step-by-step explanation:

n+1=4(n-8)

11+1=4(11-8)

12=4(3)

12=12

3 0

3 years ago

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How do I get the answer?

rewona [7]

Calculator my man calculator

4 0

3 years ago

Find the perimeter (add all sides) of a square when side a= - 41x²

Dafna11 [192]

Answer:

-164x^2

Step-by-step explanation:

The Perimeter of a square is 4s where s is the length of 1 side.

So P=4(-41x^2) 41*4=164 ----> P=-164x^2

5 0

3 years ago

3 litres of water is how many cups? 3 litres of water is how many cups? 1 following 5 answers 5 Report Abuse Are you sure you wa

Valentin [98]

If a cup is a regular sized cup that is 2 deciliters, and 1 liter equals 10 deciliters, that means that 1 liter = 5 cups, which means that 3 liters = 15 cups. If it is a cup that has 0.33 dl, then the correct number would be 9 cups.

8 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago