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vladimir1956 [14]
3 years ago
5

Taxi Cab Company B: $6.50 per ride and $0.50 per mile

Mathematics
1 answer:
natita [175]3 years ago
5 0

Using the slope - intercept relation, the equation which represents the cost of cab ride is y = 0.5x + 6.50

  • <em>Cost</em><em> </em><em>per</em><em> </em><em>ride</em><em> </em><em>=</em><em> </em><em>$</em><em>6.50</em>
  • <em>Cost</em><em> </em><em>per</em><em> </em><em>mile</em><em> </em><em>=</em><em> </em><em>$</em><em>0.50</em>

<u>Using the slope - intercept relation</u> :

  • y = bx + c

<em>b</em><em> </em><em>=</em><em> </em>change in cost per mile

<em>c</em><em> </em><em>=</em><em> </em>constant<em> </em>price added for every taxi ride

Hence, the expression can be written thus :

  • y = 0.5x + 6.50

Learn more : brainly.com/question/17225268

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Step-by-step explanation:

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Step-by-step explanation:

(3,4) ; (6,-1)

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Step-by-step explanation:

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In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

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As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

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⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

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3 years ago
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