Answer:
x = √(-1) = i
Since the value of √(-1) is not real.
The system has no real solution.
Step-by-step explanation:
The solution to the system of equations is at the point where they intercept each other.
y1 = y2
For the given equation;
y=x^2-2x and y=-2x-1
To get the where they intercept, we will equal both equations;
y=x^2-2x = -2x-1
x^2 - 2x = -2x - 1
x^2 - 2x + 2x + 1 =0
x^2 +1 = 0
x^2 = -1
x = √(-1) = i
Since the value of √(-1) is not real.
The system has no real solution.
Answer:
The quadratic equation has two complex solutions
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form 
is equal to
in this problem we have
Equate to cero
so
substitute in the formula
Remember that
so
therefore
The quadratic equation has two complex solutions
Answer:
Options c and d
Step-by-step explanation:
Given is a graph with period pi.
ii) The graph is discontinuous
iii) x intercepts are say (a) units to the right of y axis and repeats for every interval of pi.
Fix the function
a) y = sinx cannot be this graph because sinx is a continuous graph
b) y =cosx cannot be this graph because cosx is a continuous graph
e) y = sec x is undefined for the range (-1,1) since the given graph is defined in this interval, secx is not answer.
f)y = csc x is undefined for the range (-1,1) since the given graph is defined in this interval, cscx is not answer.
c) y=tanx is a discontinuous graph at x = odd multiples of pi/2
Hence the given graph can be of the form y =- tan (2x+a) which shows reflection over y axis,
d) y = cotx can also be this graph with adjustments for period and horizontal shift.
So answers are c and d
The answer to that question is C
