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sertanlavr [38]
3 years ago
14

Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

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Write a function rule for the area of a triangle whose base is 4 ft more than the height. What is the area of the triangle when
solong [7]

Answer:

A) Area as function of H ,

     F'(a) = 2 +H

B) Area of triangle with height 6ft = 30 ft²      

Step-by-step explanation:

Given as for a triangle ,

Let the height of triangle = H ft

And base = 4 ft + H ft

Now area of triangle = \frac{1}{2} × height  × base

                          F (a) =  \frac{1}{2} × H × ( 4ft + H ft)

Or,                      F (a) =  \frac{1}{2} × ( 4H + H² )

Now,   here Area is function of height ,

So ,                    F'(a) = \frac{1}{2}(4 + 2H)

Hence Area as function of H ,

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Now For height = 6 ft

Area of triangle = \frac{1}{2} × height × base

                          = \frac{1}{2} × H × ( 4ft + H ft)

                          = \frac{1}{2} × ( 4H + H² )

                          =  \frac{1}{2} × ( 24 + 36 )

                          = \frac{1}{2} × ( 60 )

                          = 30 ft²

Hence Area of triangle with height 6ft = 30 ft²      Answer

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Answer:

see below

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If we want it in slope intercept form

Distribute

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Answer:

<h2>z = 27°</h2>

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Answer:

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Step-by-step explanation:

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Divide both sides by <em>-2</em>

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