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Svetradugi [14.3K]
2 years ago
14

Any one smart and can help me catch up? ill give many points

Mathematics
1 answer:
Sergio [31]2 years ago
7 0

Answer:

4/15

Step-by-step explanation:

1) find common denominator, 15 in this problem

\frac{4}{5}= \frac{12}{15}

2) solve

\frac{12}{15}- \frac{8}{15} = \frac{4}{15}

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The slope of a hill next to a highway decreases 2 vertical feet for every 3 horizontal feet away from the highway.
Novay_Z [31]

Slope is the change in Y ( vertical) over the change in X( horizontal).

The slope would be -2 /3

You would multiply the horizontal distance by the slope:

-2/3 x 12 = -8

The answer would be D. v(h)=-2/3h, and the vertical distance is -8 feet.

8 0
3 years ago
Help!!! I have no idea how to do this
aalyn [17]

Answer:

tan53=x/14

Step-by-step explanation:

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4 0
3 years ago
6x + 4x - 1 = 2(5x + 4)
garik1379 [7]

Answer: no solutions

Step-by-step explanation:

8 0
3 years ago
WHAT IS THE VALUE OF X?
Tanzania [10]

It is a similar triangle so the side length of the smaller triangle (x and x-2) are in the same ratio as the bigger triangle (2x+5 and 2x-1). As the ratio is the same, you can equate them and solve for x.

7 0
2 years ago
In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=2, what is
Alex777 [14]

Answer:

<em>The area of the shaded region is 3.</em>

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

A_s=2 * A_t

Where At is the area of each triangle.

\displaystyle A_t=\frac{AB*BC/2}{2}

\displaystyle A_t=\frac{AB*BC}{4}

We know AB=3 and BC=2, thus:

\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}

Simplifying:

\displaystyle A_t=\frac{3}{2}

Finally:

\displaystyle A_s=2 * \frac{3}{2}

A_s=3

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

3 0
2 years ago
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