$\text{For angle N,}\\\\PQ= \text{Perpendicular.}\\\\QN = \text{Hypotenuse.}\\\\\text{Now,}\\\\\sin N = \dfrac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\\\~~~~~~~=\dfrac{QP}{QN}$

5 0

2 years ago

The depth of an underwater camera on a cable anchored to the sea floor is proportional to the time. The table records the time i

SOVA2 [1]

Answer:

20=-1

60=-3

100=-5

240=-12

Step-by-step explanation:

divide time and depth by 20

4 0

3 years ago

What is the value of sin2a + cos2a + sec2a-tan2a <br> Please

Artemon [7]

Answer:

Step-by-step explanation:

sin²a + cos²a + sec²a - tan²a

sin²a + cos²a = 1

1 + tan²a = sec²a

So, sec²a - tan²a = 1

sin²a + cos²a + sec²a - tan²a

= 1 + 1 = 2

5 0

3 years ago