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Brums [2.3K]
3 years ago
5

Determine if the two triangles are congruent. Please help, I need this turned in ASAP.​

Mathematics
2 answers:
bearhunter [10]3 years ago
8 0

Answer:

Step-by-step explanation:

tooooooooonnnniiighhhht

Ymorist [56]3 years ago
4 0

Answer:

Two triangles are congruent if they meet one of the following criteria. : All three pairs of corresponding sides are equal.  Two pairs of corresponding sides and the corresponding angles between them are equal. ... and another pair of corresponding sides are equal in two right triangles.

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The high temperature in Northville one day was 14°F. The low temperature on the same day was –9°F. What was the difference betwe
strojnjashka [21]

Answer:

-15

Step-by-step explanation: you have to think about it like a chat which means you have to count and with that being said that’s how I got -15


6 0
3 years ago
Refer to the random sample of customer order totals with an average of $78.25 and a population standard deviation of $22.50. a.
zysi [14]

Answer:

a) 78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416

78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084

b) 78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989

78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

d)   ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

Solving for n we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

And replacing the info we have:

n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55

Step-by-step explanation:

Part a

For this case we have the following data given

\bar X = 78.25 represent the sample mean for the customer order totals

\sigma =22.50 represent the population deviation

n= 40 represent the sample size selected

The confidence level is 90% or 0.90 and the significance level would be \alpha=0.1 and \alpha/2 = 0.05 and the critical value from the normal standard distirbution would be given by:

z_{\alpha/2}=1.64

And the confidence interval is given by:

\bar X -z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

And replacing we got:

78.25- 1.64 \frac{22.50}{\sqrt{40}}= 72.416

78.25+ 1.64 \frac{22.50}{\sqrt{40}}= 84.084

Part b

The sample size is now n = 75, but the same confidence so the new interval would be:

78.25- 1.64 \frac{22.50}{\sqrt{75}}= 73.989

78.25+ 1.64 \frac{22.50}{\sqrt{75}}= 82.511

Part c

For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower

Part d

The margin of error is given by:

 ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

Solving for n we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

And replacing the info we have:

n=(\frac{1.640(22.50)}{5})^2 =54.46 \approx 55

3 0
3 years ago
from start to finish, a machine can fill a bottle of water,seal it,label it, and pack it in 8.6 seconds. About how many bottles
Sphinxa [80]
About 55.8 (i suggest rounding up to 56) are packed in 480 seconds. just divide 480 by 8.6 to get the answer 55.8

5 0
3 years ago
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Find the greatest common factor 27x2y2, 45x2
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Answer:

I love algebra anyways

The ans is in the picture with the  steps how i got it

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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What is the exact distance from (–4, –2) to (4, 6)? A. 24−−√units
aliina [53]
I hope this helps you

7 0
3 years ago
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