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navik [9.2K]
2 years ago
11

Solve for p. p + 36 = 73 p =

Mathematics
2 answers:
andrew-mc [135]2 years ago
7 0

Answer:

37

Step-by-step explanation:

andrew-mc [135]2 years ago
3 0

Answer:

p=37

Step-by-step explanation:

to get p by its self, you would do:

p+36=73

 -36=-36

p=37

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What are the roots of the equation? <br> 2x^2+x=6
fredd [130]

Answer:

They would be 3/2 & -2.

4 0
2 years ago
Read 2 more answers
A line that includes the point (-3,-4) and (-4,f ) has a slope of 6. What is the value of f?
Eduardwww [97]

Answer:

f = -10

( -3, -4) ( - 4 , -10)

Step-by-step explanation:

Formula for slope

m =( y_2 - y_1)/(x _2 - x _1)

m = 6

6 = (y_2 - y_1) / (x _2 - x_1)

Substitute the points

( -3 , -4) ( -4 , f)

x_1 = -3

y_1 = -4

x_2 = -4

y_2 = f

Insert the values into

6 = (y_2 - y_1) / (x_2 - x_1)

6 = (f - (-4))/ ( -4 - (-3)

6 = ( f + 4)/ ( -4 + 3)

Cross multiply

6 ( -4 + 3) = f + 4

6 ( -1) = f + 4

-6 = f + 4

-6 - 4 = f

f = -6 - 4

f = -10

( -3 , -4) ( -3 , f)

The value of f is -10

( -3 , -4) ( -3 , -10)

8 0
3 years ago
2x + 3x + 4 equals .
RUDIKE [14]
Add like terms
only add x's together
2x+3x=5x

we can't add x's and numbres so
answer is 5x+4
7 0
3 years ago
Suppose it is known that for a given differentiable function y=f(x), its tangent line (local linearization) at the point where a
AleksandrR [38]

Answer:

y(-4) = 5

y'(-4) = -7

Step-by-step explanation:

Hi!

Since the tangent line T and the curve y must coincide at x=-4

y(-4) = T(-4) = 5

On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7

That is:

y'(-4) = -7

6 0
2 years ago
Determine the rate of change of the following coordinates
OleMash [197]

Answer:

-4

Step-by-step explanation:

 

4 0
3 years ago
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