Answer:
The amount is $418.35 and the interest is $98.35
Step-by-step explanation:
Answer: hello your question to the given scenerio is missing below is the missing question
question: Does this setting represent a Binomial distribution ?
answer : Yes the setting represents a Binomial distribution
Step-by-step explanation:
The setting represents a Binomial distribution, because the criteria's for a Binomial distribution is all present which are
- The random variable ( number of times a crinkled paper is picked ) is represented as Y
- Each sample is drawn independently and with replacement
- there are only two outcomes ( success or failure )
- Number of trials is given as 10
- probability of success = 25 / 100 = 0.25
Answer:
Answer is x = -7/6
Step-by-step explanation:
please look at the image
You will need to use this formula:
<span>Years = {log(total) -log(Principal)} ÷ log(1 + rate)
Years = [log(15,000) - log(2,500)] / log (1.0525)
</span>
<span>
<span>
<span>
4.1760912591
</span>
</span>
</span>
-
<span>
<span>
<span>
3.3979400087
</span>
</span>
</span>
/
<span>
<span>
<span>
0.0222221045
</span>
</span>
</span>
=
<span>
<span>
<span>
0.7781512504
</span>
</span>
</span>
/ <span>
<span>
<span>
0.0222221045 =
</span></span></span>
<span>
<span>
<span>
35.0169917705
</span>
</span>
</span>
years
About 35 years
You'll find the formula here: http://www.1728.org/compint2.htm
And a compound interest calculator here: http://www.1728.org/compint.htm
(You'll find both are helpful for this problem).
Answer:
Mean and IQR
Step-by-step explanation:
The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.
For company A:
Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.
Hence, the mean will be the best measure of centre rather Than the median in this case.
For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.
