Answer:
1
Step-by-step explanation:
-f + 2 + 4f = 8 - 3
3f = 6 - 3
3f = 3
f = 1
Answer:
3 + 2 = 5
5 x 5 = 25(5^2 = 25)
25 - 7 = 18
Step-by-step explanation:
Solve in parenthesis first then do exponents then perform the subtraction.
Using PEMDAS it will be a LOT more easier.
Answer:
the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Step-by-step explanation:
From the given question.
Let p be the length of the of the printed material
Let q be the width of the of the printed material
Therefore pq = 2400 cm ²
q = 
To find the dimensions of the poster; we have:
the length of the poster to be p+30 and the width to be 
The area of the printed material can now be: 
=
Let differentiate with respect to p; we have

Also;

For the smallest area 


p² = 3600
p =√3600
p = 60
Since p = 60 ; replace p = 60 in the expression q =
to solve for q;
q =
q = 
q = 40
Thus; the printed material has the length of 60 cm and the width of 40cm
the length of the poster = p+30 = 60 +30 = 90 cm
the width of the poster =
=
= 40 + 20 = 60
Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
(a + 1)(a² + 2a + 1)
= a(a² + 2a + 1) + 1(a² + 2a + 1)
= a³ + 2a² + a + a² + 2a + 1
= a³ + 3a² + 3a + 1
Answer: b