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Phantasy [73]
3 years ago
8

Suppose ABCD is a rectangle. IF AB = 10 and AD = 6, find BX to the nearest tenth. А A a. 4.0 b. 5.8 c. 11.7 d. 8.0 I​

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0

find you r answer in the attached image and please mark as brainliest if you find it helpful:

also i am assuming that you meant to type BD rather than BX

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You have ratios 3:4, 4:3, 2:5 and 5:2. Each of these ratios is such that in total gives 7.

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As you can see the closest point to point B is point S, because it lies 2 parts to the left from point B and and this amount of parts is the smallest one.

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