Answer:
A.) About 90
Step-by-step explanation:
From the given table, the biologist tagged 150 trout. Also, he recaptured a total of 100 trouts of which 60 were recaptured with tags.
Thus, let the trout population in the lake be represented by x,
= 
Cross multiply to have;
100 × x = 60 × 150
100x = 9000
Divide both sides by 100,
x = 
= 90
Therefore, the trout population is about 90 in the lake.
Just start squaring numbers! 10² = 100, so to find perfect squares bigger than that, we can just increase the base. 11² = 121, and 12² = 144, and both of those meet our requirements, so we could choose 121 and 144 as our examples.
We can calculate using cosinus method in triangle
c² = a² + b² - 2ab cos c
Plug in the number to the formula
c² = a² + b² - 2ab cos c
c² = 10² + 8² - 2(10)(8) cos 105°
c² = 100 + 64 - 160 cos 105°
c² = 164 - 160 (-0.26)
c² = 164 + 41.6
c² = 205.6
c = √205.6
c =14.34
C is 14.34 unit length
3^6 power. it would be 3 to the 6th power
