the slope of a graphed line is 2/3 and the y-intercept is (0,4) what is the slope-intercept equation of the line

1 answer:

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Idk tbh wat is a great game for me so I can play with the kids and play it for a while and then play me and play me when I get home I wanna Play is time

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IF U SEE THIS PLZ HELP IM FAILING! 20 POINTS AND WILL MARK BRAINLIEST!

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Answer:

mc013-1.j pg

Step-by-step explanation:

The answer is A

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I’ll mark brainliest if correct lol

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Step-by-step explanation:

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Rewrite in Polar Form....<br> x^(2)+y^(2)-6y-8=0

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$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

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the slope of a graphed line is 2/3 and the y-intercept is (0,4) what is the slope-intercept equation of the line​

the slope of a graphed line is 2/3 and the y-intercept is (0,4) what is the slope-intercept equation of the line