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devlian [24]
3 years ago
13

47. Health care costs per capita Rising health care costs

Mathematics
1 answer:
horrorfan [7]3 years ago
6 0
NHE grew 4.6% to $3.8 trillion in 2019, or $11,582 per person, and accounted for 17.7% of Gross Domestic Product (GDP).
Medicare spending grew 6.7% to $799.4 billion in 2019, or 21 percent of total NHE.
Medicaid spending grew 2.9% to $613.5 billion in 2019, or 16 percent of total NHE.
Private health insurance spending grew 3.7% to $1,195.1 billion in 2019, or 31 percent of total NHE.
Out of pocket spending grew 4.6% to $406.5 billion in 2019, or 11 percent of total NHE.
Hospital expenditures grew 6.2% to $1,192.0 billion in 2019, faster than the 4.2% growth in 2018.
Physician and clinical services expenditures grew 4.6% to $772.1 billion in 2019, a faster growth than the 4.0% in 2018.
Prescription drug spending increased 5.7% to $369.7 billion in 2019, faster than the 3.8% growth in 2018.
The largest shares of total health spending were sponsored by the federal government (29.0 percent) and the households (28.4 percent). The private business share of health spending accounted for 19.1 percent of total health care spending, state and local governments accounted for 16.1 percent, and other private revenues accounted for 7.5 percent.
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Please help me with math
KatRina [158]

Answer:

The answer is ±3i

Step-by-step explanation:

Can be Rewritten as:

±(√-1 × √9) where √-1 = i and √9=3

Therefore Answer is ±3i

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3 years ago
What is the answer to the question
fenix001 [56]

Answer:

Step-by-step explanation:

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Mark’s food for lunch cost $12. The restaurant added a 5 percent sales tax, $0.60, to the bill. Mark wants to pay a 20 percent t
kotykmax [81]

12+.60+ 12.60

12.60*20%

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4 years ago
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Simplify the following expression.<br><br> 0.466 × 1.2
Ganezh [65]

Answer:

0.466 \times 1.2 \\  \frac{699}{1250}   \:  \: or \:  \: 0.55

6 0
3 years ago
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Wal-Mart conducted a study to check the accuracy of checkout scanners at its stores. At each of the 60 randomly selected Wal-Mar
Mamont248 [21]

Answer:

a

The 95% confidence interval is

   0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

b

  Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

c

 n =  125  \  stores  

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  60  

    The number of stores that had more than 2 items price incorrectly is  k =  52  

   

Generally the sample proportion is mathematically represented as  

             \^ p  =  \frac{ k }{ n }

=>          \^ p  =  \frac{ 52 }{ 60 }

=>          \^ p  =  0.867

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E =  1.96  * \sqrt{\frac{ 0.867  (1- 0.867)}{60} }

=>   E =  0.0859

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.867  - 0.0859  <  p <  0.867  +  0.0859

=>    0.7811 <  p <  0.9529

Generally the interval above can interpreted as

    There is 95% confidence that the true proportion of Wal-Mart stores that have more than 2 items priced inaccurately per 100 items scanned lie within the interval  

Considering question b

Generally  99% is outside the interval obtained in a  above then the claim of Wal-mart is not believable  

   

Considering question c

From the question we are told that

    The margin of error is  E = 0.05

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the sample size is mathematically represented as  

    n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=> n=  [\frac{1.645 }}{0.05} ]^2 * 0.867  (1 - 0.867 )

=>   n =  125  \  stores  

4 0
3 years ago
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