A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
One could be |x|<-2
This could be one since no matter what you put in for x, it will always be positive.
Answer:
Hence the correct option is the last one . The triangle is an obtuse angled triangle.
Step-by-step explanation:
i) the sum of any two sides added together is greater than the third side hence this is a triangle.
ii) it is<em><u> not</u></em> a right angled triangle as
and 
iii) the triangle is not acute from ii) above
iv) the triangle is an obtuse triangle from ii) above.
Answer:
the pic is block
Step-by-step explanation: