A sample of He gas in a 2 L container has a pressure of 6 atm. The He is moved into a 3 L container of Ne gas at 8 atm. What is
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1. The bar of metal is not pure gold.
2. The volume of 50.0 g of air is 42,016 mL.
3. The mass of the pure aluminum is 135 g.
4. The light beam's wavelength in meters is 475 x m.
The density of a substance is the ratio of the mass of the substance and its volume.
Density = mass/volume.
For the first problem: mass = 57.3 g, volume = 4.7 cm3
Density of the metal = 57.3/4.7
= 12.19 g/cm3
The density of gold is 19.3 g/cm3. Thus, the bar of metal is not pure gold.
For the second problem: density = 1.19 x g/ml, mass = 50.0 g
Volume = mass/density
= 50/1.19 x
= 42,016 ml
The volume of 50.0 g of air is 42,016 mL.
For the third problem: density = 2.70 g/ml, volume = 50.0 ml.
Mass = density x volume
= 2.70 x 50
= 135 g
The mass of the pure aluminum is 135 g.
Lastly:
nano =
475 nm = 475 x m
The light beam's wavelength in meters is 475 x m.
More on density can be found here: brainly.com/question/15164682
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