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Goshia [24]
3 years ago
14

Write balanced net ionic equations for the reactions that occur in each of the following cases. Identify the spectator ion or io

ns in each reaction. Cr2(SO4)3(aq)+(NH4)2CO3(aq)−→ Cr2(SO4)3(aq)+(NH4)2CO3(aq)→ Ba(NO3)2(aq)+K2SO4(aq)−→ Ba(NO3)2(aq)+K2SO4(aq)→ Fe(NO3)2(aq)+KOH(aq)−→
Chemistry
1 answer:
Dmitrij [34]3 years ago
3 0

Answer :

(a) The net ionic equation will be,

2Cr^{2+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)

The spectator ions are, NH_4^{+}\text{ and }SO_4^{2-}

(b) The net ionic equation will be,

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

The spectator ions are, K^{+}\text{ and }NO_3^{-}

(c) The net ionic equation will be,

Fe^{2+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)

The spectator ions are, K^{+}\text{ and }NO_3^{-}

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The given balanced ionic equation will be,

Cr_2(SO_4)_3(aq)+3(NH_4)_2CO_3(aq)\rightarrow 3(NH_4)_2SO_4(aq)+Cr_2(CO_3)_3(s)

The ionic equation in separated aqueous solution will be,

2Cr^{2+}(aq)+3SO_4^{2-}(aq)+6NH_4^{+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)+6NH_4^{+}(aq)+3SO_4^{2-}(aq)

In this equation, NH_4^{+}\text{ and }SO_4^{2-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2Cr^{2+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)

(b) The given balanced ionic equation will be,

Ba(NO_3)_2(aq)+K_2SO_4(aq)\rightarrow 2KNO_3(aq)+BaSO_4(s)

The ionic equation in separated aqueous solution will be,

Ba^{2+}(aq)+2NO_3^{-}(aq)+2K^{+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)+2K^{+}(aq)+2NO_3^{-}(aq)

In this equation, K^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)

(c) The given balanced ionic equation will be,

Fe(NO_3)_2(aq)+2KOH(aq)\rightarrow 2KNO_3(aq)+Fe(OH)_2(s)

The ionic equation in separated aqueous solution will be,

Fe^{2+}(aq)+2NO_3^{-}(aq)+2K^{+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)+2K^{+}(aq)+2NO_3^{-}(aq)

In this equation, K^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Fe^{2+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)

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