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geniusboy [140]
3 years ago
15

The answer is Drusilla

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

Drusilla

Step-by-step explanation:

the answer is Drusilla

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Help Me Find The Inequality of the graph ​
Pie
Hope this help Can ask any doubt

7 0
3 years ago
If QR = 6x + 1, PR = 14x-13, and PQ = 5x -2, find PR.
monitta

Answer:

Um I will report ur answer

Step-by-step explanation:

5 0
3 years ago
Pic below ......................................
nekit [7.7K]

Answer:

d = \sqrt{65}

Step-by-step explanation:

We need to find the distance between the points (5, 2) and (1, 9). In order to do this, we will use something called the distance formula. The distance formula is written as follows:

d = \sqrt{(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}

Now we need to plug in our points which we have given in the form (x, y):

d = \sqrt{(5-1)^{2}+(2-9)^{2}}

Next, perform the operation of subtraction inside the parentheses to simplify:

d = \sqrt{(4)^{2}+(-7)^{2}}

The exponent is the next step in the order of operations, so square 4 and -7:

d = \sqrt{16+49}

Finally, add 16 to 49:

d = \sqrt{65}

The square root of 65 cannot be simplified further, but an approximation can be made.

\sqrt{65}  ≈ 8.062257748

7 0
3 years ago
A rectangular lawn, 100 feet long by 50 feet wide, is to have two sidewalks installed that will cut the lawn in half both ways,
Damm [24]

Answer:

3.41 feet

Step-by-step explanation:

Area = Length × Breath

Area of the rectangular lawn = 100 × 50

                                                = 5000 feet²

The sidewalk must occupy an area no more than 10% of the total lawn area.

So, the area of the sidewalk would be not more than  = 10% × 5000

                                                                                         = 0.10 × 5000

                                                                                        = 500 feet²

Let the width of the sidewalk = x feet

area of the side walk = (L×W of the long way) + ((L-x)×W of the short way)

(100 × x) + ((50 - x) × x) < 500

100x + (50-x)(x) < 500

-x²  + 150x < 500

-x² + 150x = 500

-x² + 150x - 500 = 0

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\frac{(-150)\pm\sqrt{(150)^2-4(-1)(-500)} }{2(-1)}

x=\frac{-150\pm \sqrt{20500} }{-2}

x=75-5\sqrt{205} or x=75+5\sqrt{205}

x = 3.41089 ≈ 3.41 feet  or  x = 146.58

Therefore, width of the sidewalk would be 3.41 feet.

5 0
3 years ago
Plz help me with this
forsale [732]

Answer:

\frac{31x}{30}

Step-by-step explanation:

Before adding we require the fractions to have a common denominator

The lowest common denominator of 2, 5 and 3 is 30, thus

\frac{15x}{15(2)} + \frac{6x}{6(5)} + \frac{10x}{10(3)}

= \frac{15x}{30} + \frac{6x}{30} + \frac{10x}{30}

Add the numerators leaving the denominator

= \frac{15x+6x+10x}{30} = \frac{31x}{30}

5 0
4 years ago
Read 2 more answers
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