3∅ can be rewritten as (2∅+∅)
sin(3∅) = sin(2∅ + ∅<span>)
Opening brackets on the right hand side;
= sin2</span>∅ cos ∅ + cos2∅sin<span>∅
</span><span>This simplifies to;
= 2sin</span>∅cos^2∅ + sin∅ (1- 2sin^2∅<span>)
= sin</span>∅ (2cos^2∅ + 1 - 2sin^2∅<span>)
= sin</span>∅ (2(1 - sin^2∅) +1-2sin^2∅<span>)
= 3sin</span>∅ - 4sin^3<span>∅</span>
Answer:
Step-by-step explanation:
Rewrite this quadratic equation in standard form: 2n^2 + 3n + 54 = 0. Identify the coefficients of the n terms: they are 2, 3, 54.
Find the discriminant b^2 - 4ac: It is 3^2 - 4(2)(54), or -423. The negative sign tells us that this quadratic has two unequal, complex roots, which are:
-(3) ± i√423 -3 ± i√423
n = ------------------- = ------------------
2(2) 4
Answer:
im taking the same test lol
Step-by-step explanation:
