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Setler [38]
3 years ago
10

X^2 + 8x + 7 = 0

Mathematics
1 answer:
dsp733 years ago
7 0

Answer:

x - intercepts: -1, -7

Solutions: [is the x-intercepts] -1,-7

Factors: (x+1)(x+7)

Vertex: -4, -9

Axis of symmetry: x = -4

Step-by-step explanation:

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The total attendance at a school play was 1250. The cost of tickets was $6.00 for students
daser333 [38]

Answer:

look at picture

Step-by-step explanation:

x: student tickets

y: adult tickets

7 0
4 years ago
Use the following vectors to answer parts​ (a) and​ (b). v1equals=[Start 3 By 1 Matrix 1st Row 1st Column 1 2nd Row 1st Column n
erik [133]

Answer:

(1) No matter what's the value of h, \vec{v}_3 is never in the span of \vec{v}_1 and \vec{v}_2.

(2) The three vectors \vec{v}_1, \vec{v}_2, and \vec{v}_3 are always linearly dependent for all real h.

Step-by-step explanation:

<h3>(a)</h3>

If \vec{v}_3 is in the span of \vec{v}_1 and \vec{v}_2, there need to exist real a and b such that

a\; \vec{v}_1 + b\; \vec{v}_2 = \vec{v}_3.

Assume that such a and b do exist.

In other words,

\displaystyle a \left[\begin{array}{c}{1 \\ -4\\2} \end{array}\right] + b\left[\begin{array}{c}{-4 \\ 16\\-8}\end{array}\right] = \left[\begin{array}{c}5 \\7 \\ h\end{array}\right].

\displaystyle \left[\begin{array}{c}{a \\ -4a\\2a} \end{array}\right] + \left[\begin{array}{c}{-4b \\ 16b\\-8b}\end{array}\right] = \left[\begin{array}{c}5 \\7 \\ h\end{array}\right].

\left\{\begin{array}{rrcr} a & - 4b &=& 5\\ -4a & + 16b &= &7\\2a & -8b & =&h\end{aligned}\right..

Rewrite as an augmented matrix and row-reduce:

\displaystyle \left[ \begin{array}{cc|c} 1 & -4 & 5 \\ -4 & 16 & 7 \\ 2 & -8 & h\end{array}\right].

(Add four times row one to row two and -2 times row one to row three.)

\displaystyle \sim \left[ \begin{array}{cc|c} 1 & -4 & 5 \\ 0 & 0 & 27 \\ 0 & 0 & h - 10\end{array}\right].

Note that in row two,

  • Left-hand side: 0;
  • Right-hand side: 27\neq 0.

In other words, this system is inconsistent. There's no real a and b that would satisfy the condition

a\; \vec{v}_1 + b\; \vec{v}_2 = \vec{v}_3.

Hence \forall h \in \mathbb{R}, \quad \vec{v}_3\not \in \text{Span}\{\vec{v}_1, \vec{v}_2\}.

There's no real h that allows h, \vec{v}_3 to be part of the span of \vec{v}_1 and \vec{v}_2.

<h3>(b)</h3>

If the three vectors are linearly dependent, at least one of them can be expressed as the linear combination of the other two.

Note that

\vec{v}_2 = (-4)\vec{v}_1 + 0 \; \vec{v}_3. In other words, \vec{v}_2 can be written as the linear combination of the other two vectors. Additionally, since the coefficient in front of \vec{v}_3 is zero, neither the exact value of \vec{v}_3 nor the value of h will make a difference. Therefore, for all h \in \mathbb{R}, the three vectors \vec{v}_1, \vec{v}_2, and \vec{v}_3 are linearly dependent.

8 0
3 years ago
What is the surface area of the rectangular prism
anastassius [24]

340 you were right

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Plz help urgently i dont know how to do it
masha68 [24]

Answer:

11

Step-by-step explanation:

1650/15/10 = 11

6 0
4 years ago
The lengths of the sides of a quadrilateral are consecutive even integers. twice the length of the shortest side plus the length
spayn [35]
To solve this problem you must apply the proccedure shown below:

 1. You have the following information given in the problem above: <span>twice the length of the shortest side plus the length of the longest side is 248 inches.

 2. Therefore, keeping on mind the information above, you have:

 x: the shortest side
 x+6: the longest side

 2x+(x+6)=248
 3x+6=248
 3x=242
 x=242/3
 x=80.66 (The shortest side)

 x+6=80.66+6=86.66 (The longest side)

 The answer is: 86.66
</span>
4 0
4 years ago
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