Answer:
The Least Common Denominator of 3/4, 4/5 and 2/3
Would be,
4 × 5 × 3 = 60
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>60</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>L.C.D</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>3</u></em><em><u>/</u></em><em><u>4</u></em><em><u>,</u></em><em><u> </u></em><em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>2</u></em><em><u>/</u></em><em><u>3</u></em>
Answer:
5.6 x 10 2
Step-by-step explanation:
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)
Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141
(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71
(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000
</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x
taking "ln" on both sides:
ln(4.797) = ln(1.19)^x
ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)
Answer:
v = 80 mph
Step-by-step explanation:
Given that,
The distance from Wakefield to London is 180 miles.
The train travels this distance in 2 hours 15 minutes.
We need to find the average speed of the train. The average speed of the train is equal to the total distance covered divided by the time taken.
So, the required average speed of the train is 80 mph.