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zvonat [6]
2 years ago
8

27x39 Plz help jk jk

Mathematics
1 answer:
lesya [120]2 years ago
8 0

Answer: 1053

Step-by-step explanation: ...............................

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Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
4 years ago
Simpify the expression. -2(y + 3) -7y
jenyasd209 [6]
-2y-6-7y
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I hope that this helps!
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3 years ago
26m<br> 18m<br> 4m<br> 39m<br> Need to find the area of this shape anyone?
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Answer:

611m²

Step-by-step explanation:

Too difficult to explain by words, it's in the picture.

Hope this helps!

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3 years ago
5300 divided by 10 to the third power
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P(for men | botanic) = 5/18

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