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Radda [10]
3 years ago
6

The shortest distance from any point to a line is a

Mathematics
1 answer:
VMariaS [17]3 years ago
7 0
... is the length of the line perpendicular to the given line that also passes through the given point.
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Sketch a rectangular prism that has a volume of 500 cm3 and some sides that are not whole numbers.
Sergeeva-Olga [200]

do u need an answer  or are you telling people to do so whcih one is is

Step-by-step explanation:

im not being rude thats just how i talk

please mark brainlest

the answr is a

5 0
2 years ago
A new pencil is 19 centimeters long. Levi uses it for a month. The pencil now measures 8 centimeters.
pogonyaev

Answer:

11 cm

Step-by-step explanation:

Given:

Length of new pencil = 19 cm

Length of pencil after using a month = 8 cm

Question asked:

The pencil is centimeters shorter now than when it was new = ?

Solution:

Length of new pencil = 19 cm

Length of pencil after using a month =  8 cm

The pencil is centimeters shorter now than when it was new = 19 cm -  8 cm

                                                                                                     = 11 cm

Length of pencil has been used during a month = 11 cm

8 0
3 years ago
6. How do you find the slope of a line?
S_A_V [24]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
3.) A glass of water is being filled up slowly. It initially starts out with 4
maria [59]

Answer:

  8 minutes

Step-by-step explanation:

The amount in the glass after m minutes can be described by ...

  a = 4 + 3/2m

We want to find m when a=16, so ...

  16 = 4 + 3/2m

  12 = 3/2m . . . . . subtract 4

  8 = m . . . . . . . . . multiply by 2/3

It will take 8 minutes to fill the glass.

4 0
3 years ago
Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor
Liula [17]

Answer:

(AD)^2 + (CD)^2 = (CA)^2 and (CD)^2 + (BD)^2 = (CB)^2

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

Hypothenuse = CA

Opposite = CD

Adjacent = AD

By Pythagoras Theorem, we have

(AD)^2 + (CD)^2 = (CA)^2

Considering CBD

From the attachment, we have that:

Hypothenuse = CB

Opposite = CD

Adjacent = BD

By Pythagoras Theorem, we have:

(CD)^2 + (BD)^2 = (CB)^2

4 0
2 years ago
Read 2 more answers
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