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tatyana61 [14]
3 years ago
7

Simply 7/4 squared ​

Mathematics
2 answers:
trapecia [35]3 years ago
7 0
The answer to your question is 49/16
klemol [59]3 years ago
5 0

Answer:

0.4375

Step-by-step explanation:

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GarryVolchara [31]

Answer:

b. C= 14+(10b)

c. C = 14+ ( 10 x 3) = 14+30 =44

Step-by-step explanation:

Hope this helps

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2 years ago
Please answer and explain the link below
Leviafan [203]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left \{ {{\sqrt{x + 1}, \ x < 3} \atop {5 - x, \ x \geq 3}} \right.

<u>Step 2: Find Right Limit</u>

  1. Substitute in variables [Right-Side Limit]:                                                      \displaystyle  \lim_{x \to 3^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^+} 5 - x = 5 - 3
  3. Subtract:                                                                                                         \displaystyle  \lim_{x \to 3^+} 5 - x = 2

∴ the right-side limit equals 2.

<u>Step 3: Find Left Limit</u>

  1. Substitute in variables [Left-Side Limit]:                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1}
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{3 + 1}
  3. [√Radical] Add:                                                                                             \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{4}
  4. [√Radical] Evaluate:                                                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = 2

∴ the left-side limit equals 2.

<u>Step 4: Find Limit</u>

<em>The right and left-side limits are equal.</em>

∴  \displaystyle  \lim_{x \to 3} f(x) = 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

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Insert a picture, please.

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\bf \cfrac{3}{x+4}+\cfrac{2}{x^2-16}\implies \cfrac{3}{x+4}+\cfrac{2}{\stackrel{\textit{difference of squares}}{x^2-4^2}}\implies \cfrac{3}{x+4}+\cfrac{2}{(x-4)(x+4)}\\\\\\\stackrel{\textit{so our LCD will be }(x-4)(x+4)}{\cfrac{(x-4)3+(1)2}{(x-4)(x+4)}}\implies \cfrac{3x-12+2}{(x-4)(x+4)}\implies \cfrac{3x-10}{(x-4)(x+4)}

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4 years ago
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What is another way to represent the ratio 40:1?
Shtirlitz [24]
40/1 is the other way
7 0
4 years ago
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