Answer:
f(n) = a+200(n -1)
Step-by-step explanation:
The constant difference between terms indicates the sequence is an arithmetic one. The explicit formula for an arithmetic sequence is ...
an = a1 + d(n -1)
where a1 is the first term and d is the common difference.
Your first term is "a", and your common difference is 200, so the n-th term of the sequence is ...
an = a + 200(n -1)
Written as a function of n, this is ...
f(n) = a + 200(n -1)
_____
Based on the problem description, we cannot tell how n relates to time, so we have created an f(n) that gives the same result as the recursive definition of f(n).
Question 1) x=4
the rest I rly dk
The intersection of the gaphs of the two equations are at point (-2, 0) and (3, 5) which are the solutions to the system of equations.
We have the following functions:
f (x) = x ^ 2 + 1
g (x) = 1 / x
Multiplying we have:
(f * g) (x) = (x ^ 2 + 1) * (1 / x)
Rewriting:
(f * g) (x) = ((x ^ 2 + 1) / x)
Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
We have then:
All reals except number 0
Answer:
b. all real numbers, except 0
