Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
675 : 5 = 135
135 : 5 = 27
27 : 3 = 9
9 : 3 = 3
3 : 3 = 1
675 = 5 · 5 · 3 · 3 · 3 = 5² · 3³
Answer:
D) $8.20
Step-by-step explanation:
82 x 0.1 = 8.2
C = 10d+ 45 ? Hope this helps? Let me know if it’s right or not.
2a - b....a = 2 and b = 3
2(2) - 3 =
4 - 3 =
1
