Help me on these 2 please
1 answer:
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<u>Given</u>:
The given triangle QPO is a right triangle.
The length of QP is 5 units.
The length of OP is (x + 5) units.
The length of QO is (x + 6) units.
We need to determine the hypotenuse of the triangle QPO.
<u>Value of x:</u>
The value of x can be determined using the Pythagorean theorem.
Thus, we have;
Substituting the values, we get;
Expanding, we get;
Adding the like terms, we get;
Thus, the value of x is 7.
<u>Length of the hypotenuse:</u>
The hypotenuse of the triangle QPO is QO.
Substituting x = 7 in the length of QO, we get;
Thus, the length of the hypotenuse is 13 units.
Hence, Option D is the correct answer.
Answer:
Cos <B = 3/5
Step-by-step explanation:
Find the diagram attached
From the diagram, we have;
Hypotenuse BC = 80
Opposite to <B = AC =64
Adjacent AB = 48
According to SOH CAH TOA identity
Cos theta = adjacent/hypotenuse
Cos<B = AB/BC
Cos <B = 48/80
Express in its simplest form
Cos <B = (16*3)/(16*5)
Cos <B = 3/5
Hence the ratio of cos<B in its simplest form is 3/5
