To be blunt, it looks like you just copy/pasted a wall of text from whatever you're working on. Ask an actual question, and format the wall of text so that we don't have to decipher it ourselves. Don't expect people to help solve a problem like that if it looks like you gave no thought in posting it
Answer:
17/7 days will be the answer
Step-by-step explanation:
Answer:
The first one is linear, the second one is not linear, and the third one is linear.
Step-by-step explanation:
Answer:
The solutions are (-√6,0) and (√6,0)
(-√5,-1) and (√5,-1)
Step-by-step explanation:
The equations are:

and

We make y the subject in the second equation to get;

We substitute into the first equation to get:


and 
The solutions are (-√6,0) and (√6,0)
(-√5,-1) and (√5,-1)