Constructing What? you did not finish the question
<span>Say the code only needed to be one number long. Going from 0-9, there are ten digits. Therefore, there are ten unique codes.
Now say the code has to be two numbers long. There are ten possibilities
for the first digit, 0-9. But the second digit only has nine
possibilities, since each number has to be different. (The first number
might be 0, so the second can only go from 1-9) For each of the first
ten possibilities, there are nine possibilities for the second. We
multiply those two numbers together, 10 * 9, and we get 90.
Now we just extend the logic. The third number only has eight
possibilities, while the fourth number only has seven. 10 * 9 * 8 * 7 =
5040 possible codes. I hope this helped! has a great day! :)</span>
Answer:
the answer is three(3)..use calculator
Answer:
50%
Step-by-step explanation:
3500 divided by 1750 is 2 which is equal to 50%
Answer:
Formula for a linear sequence is
Tn=a+(n-1)d
where Tn is the nth term
a is the first term
n is the number of term
d is common difference
