Answer:
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Step-by-step explanation:
First we have to calculate the area, for this we must multiply the length by the width
a = area
l = long = 55yd
w = width = 35yd
a = l * w
a = 55yd * 35yd
a = 1925yd²
to calculate the volume we have to multiply the area by the height
asks us for the volume for half the height so we have to divide the height by 2
a = area = 1925yd²
h = height = 5yd/2 = 2.5yd
v = volume
v = a * h
v = 1925yd² * 2.5yd
v = 4812.5yd³
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Answer:
Yes
Step-by-step explanation:
It has a 45 degree angle
Answer:
64
Step-by-step explanation:
Evaluate x^4 + 3 x^3 - 6 x^2 - 12 x - 8 where x = 3:
x^4 + 3 x^3 - 6 x^2 - 12 x - 8 = 3^4 + 3×3^3 - 6×3^2 - 12×3 - 8
3^3 = 3×3^2:
3^4 + 3×3×3^2 - 6×3^2 - 12×3 - 8
3^2 = 9:
3^4 + 3×3×9 - 6×3^2 - 12×3 - 8
3×9 = 27:
3^4 + 3×27 - 6×3^2 - 12×3 - 8
3^2 = 9:
3^4 + 3×27 - 69 - 12×3 - 8
3^4 = (3^2)^2:
(3^2)^2 + 3×27 - 6×9 - 12×3 - 8
3^2 = 9:
9^2 + 3×27 - 6×9 - 12×3 - 8
9^2 = 81:
81 + 3×27 - 6×9 - 12×3 - 8
3×27 = 81:
81 + 81 - 6×9 - 12×3 - 8
-6×9 = -54:
81 + 81 + -54 - 12×3 - 8
-12×3 = -36:
81 + 81 - 54 + -36 - 8
81 + 81 - 54 - 36 - 8 = (81 + 81) - (54 + 36 + 8):
(81 + 81) - (54 + 36 + 8)
| 8 | 1
+ | 8 | 1
1 | 6 | 2:
162 - (54 + 36 + 8)
| 1 |
| 5 | 4
| 3 | 6
+ | | 8
| 9 | 8:
162 - 98
| | 15 |
| 0 | 5 | 12
| 1 | 6 | 2
- | | 9 | 8
| 0 | 6 | 4:
Answer: 64
In order to answer this question I need to see a diagram. Do you have one?
6 is 5.5 because the length of GH is half of KL
