Find the measurement of either the leg or the hypotenuse: A = B = 21 C = 35
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D. V=12 R=12
I=V/R so Current = 1 amp
e.3 ohm resistor
V=IR
V=3 V
At the 4 ohm
4 V
And at the 5 ohm
5 volts
f. The voltage drops across the resistors add up to give the voltage supplied by the battery
4
I=V/R so Current = 1 amp
e.3 ohm resistor
V=IR
V=3 V
At the 4 ohm
4 V
And at the 5 ohm
5 volts
f. The voltage drops across the resistors add up to give the voltage supplied by the battery
4
