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3 years ago

Consider the function f(x)=8-3x^2 find the value of f(x) when x= 3

2 answers:

5 0

You start with f(x)=8-3(3)². Then, going in order of PEMDAS, you start with your exponent. So you have f(x)=8-3(9). Then multiplication, f(x)=8-27. Then your subtraction. f(x)=-19

Gelneren [198K]3 years ago

5 0

F(3)=8-3(3)^2= -19.....

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I don’t understand this one

Masja [62]

Answer:

see below

Step-by-step explanation:

Put -1 where x is in each expression and evaluate it.

You will find that the expression is zero when the numerator is zero. And you will find the numerator is zero when it has a factor that is equivalent to ...

(x +1)

Substituting x=-1 into this factor makes it be ...

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Evaluating the first expression, we have ...

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This first expression is one you want to "check."

You can see that the reason the expression is zero is that x+1 has a sum of zero. You can look for that same sum in the other expressions. (The tricky one is the one with the factor (x -(-1)). You know, of course, that -(-1) = +1.)

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4 years ago

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dusya [7]

Answer:

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Step-by-step explanation:

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Rina8888 [55]

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Step-by-step explanation:

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3 years ago

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GarryVolchara [31]

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denis23 [38]

Number of different bases for each one:
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1 2 6 ---> 1 2 6, 1 6, 2, 2 6 1 --- 3 of them
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