Find the length of rhombus whose diogonals are length 12 cm and 16 cm
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Answer:
1655
Step-by-step explanation:
Note the common difference d between consecutive terms of the sequence
d = - 1 - (- 4) = 2 - (- 1) = 5 - 2 = 8 - 5 = 3
This indicates the sequence is arithmetic with sum to n terms
=
[ 2a₁ + (n - 1)d ]
Here a₁ = - 4, d = 3 and n = 90, thus
=
[ (2 × - 4) + (89 × 3) ] = 45(- 8 + 267) = 45 × 259 = 1655
1/2 = 0.5
12 & 1/2 = 12 + 1/2 = 12 + 0.5 = 12.5
4 & 1/2 = 4 + 1/2 = 4 + 0.5 = 4.5
Refer to the diagram below. Note how I divided the figure into two rectangles.
The larger red rectangle is 12.5 feet by 10 feet. It has area 12.5*10 = 125 square feet.
The smaller blue rectangle has dimensions 4.5 feet by 5 feet (the 5 is from 15-10 = 5), so it has area 4.5*5 = 22.5 square feet
Now add up those individual areas to get the total area
125+22.5 = 147.5
Then convert that to a mixed number
147.5 = 147 + 0.5 = 147 + 1/2 = 147 & 1/2
<h3>The correct area is 147 & 1/2 feet</h3>