What is the image point of (1,4) after a translation left 5 units and down 5 units
1 answer:
You might be interested in
-----------------------------
You're very close. However, the less steep line should go through (4,7) and not some point slightly above that location. Also, the shaded region should be above both dashed lines at the same time. So you won't include the portion that I've marked in blue (see attached). Other than that, it looks great.
Answer:
20)
19)
18)
17)
16)
15)
14)
13)
12)
11)
Step-by-step explanation:
20) {−2x - y = −9
{5x - 2y = 18
⅖[5x - 2y = 18]
{−2x - y = −9
{2x - ⅘y = 7⅕ >> New Equation
__________
[Plug this back into both equations above to get the x-coordinate of 4];
_______________________________________________
19) {−5x - 8y = 17
{2x - 7y = −17
−⅞[−5x - 8y = 17]
{4⅜x + 7y = −14⅞ >> New Equation
{2x - 7y = −17
_____________
[Plug this back into both equations above to get the y-coordinate of 1];
_______________________________________________
18) {−2x + 6y = 6
{−7x + 8y = −5
−¾[−7x + 8y = −5]
{−2x + 6y = 6
{5¼x - 6y = 3¾ >> New Equation
____________
[Plug this back into both equations above to get the y-coordinate of 2];
_______________________________________________
17) {−3x - 4y = 2
{3x + 3y = −3
__________
[Plug this back into both equations above to get the x-coordinate of −2];
_______________________________________________
16) {2x + y = 20
{6x - 5y = 12
−⅓[6x - 5y = 12]
{2x + y = 20
{−2x + 1⅔y = −4 >> New Equation
____________
[Plug this back into both equations above to get the x-coordinate of 7];
_______________________________________________
15) {6x + 6y = −6
{5x + y = −13
−⅚[6x + 6y = −6]
{−5x - 5y = 5 >> New Equation
{5x + y = −13
_________
[Plug this back into both equations above to get the x-coordinate of −3];
_______________________________________________
14) {−3x + 3y = 3
{−5x + y = 13
−⅓[−3x + 3y = 3]
{x - y = −1 >> New Equation
{−5x + y = 13
_________
[Plug this back into both equations above to get the y-coordinate of −2];
_______________________________________________
13) {−3x + 3y = 4
{−x + y = 3
−⅓[−3x + 3y = 4]
{x - y = −1⅓ >> New Equation
{−x + y = 3
________
_______________________________________________
12) {−3x - 8y = 20
{−5x + y = 19
⅛[−3x - 8y = 20]
{−⅜x - y = 2½ >> New Equation
{−5x + y = 19
__________
[Plug this back into both equations above to get the y-coordinate of −1];
_______________________________________________
11) {x + 3y = 1
{−3x - 3y = −15
___________
[Plug this back into both equations above to get the y-coordinate of −2];
I am delighted to assist you anytime my friend!