2 years ago

(Find the HCF of):p^2+4pq+4q^2, p^4 + 8pq^3 and 3p^4 - 10p^2q^2+ p^3q

Mathematics

1 answer:

kow [346]2 years ago

5 0

Answer:

12pq

Step-by-step explanation:

i dont know tbh but i try my best to help out now anyways

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2 years ago

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MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

<u>Standard equation of a circle:</u>

$(x-a)^2+(y-b)^2=r^2$

(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

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<u>Additional information</u>

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

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$\implies (x-2)^2-4+(y+3)^2-9=16$

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2 years ago

I need this answered ASAP, thank you!

horsena [70]

Answer:

Part A

16y = 7x + 101

Part B

3y = 5x + 30

Part C

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Part D

x = -3

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3 years ago

Rewrite 5 times X + 5 x 8 in parenthesies

sveta [45]

Answer:

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Step-by-step explanation:

i hope this helpssss

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3 years ago

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(Find the HCF of):p^2+4pq+4q^2, p^4 + 8pq^3 and 3p^4 - 10p^2q^2+ p^3q​

(Find the HCF of):p^2+4pq+4q^2, p^4 + 8pq^3 and 3p^4 - 10p^2q^2+ p^3q