1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kodGreya [7K]
3 years ago
11

MATH HELP

Mathematics
2 answers:
vampirchik [111]3 years ago
6 0
Collect like terms which will be
(8x+4)- (2y+4y-6)=
12x-2y-6
nordsb [41]3 years ago
5 0
I think that A. 12x+2y-6 is the answer, because 8+4 is 12 and -2+4 is 2 and there is nothing to combine with the 6.
You might be interested in
What are the exact values of sin theta cos theta tan theta if (3,-4) is a point on the terminal side of theta?
malfutka [58]
\bf (\stackrel{a}{3}~,~\stackrel{b}{-4})\impliedby \textit{now let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{3^2+(-4)^2}\implies c=\sqrt{25}\implies \boxed{c=5}

\bf -------------------------------\\\\
sin(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\qquad cos(\theta )=\cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{5}}\qquad tan(\theta )=\cfrac{\stackrel{opposite}{-4}}{\stackrel{adjacent}{3}}
6 0
3 years ago
Plzz help. Giving everything.<br> D. 24.5
Lemur [1.5K]

Answer:

\frac{8}{14} = \frac{14}{x+2}  (since they're similar, set them up as a proportion to find x)

14*14 = 8(x+2) (cross multiply, solve the left side, and distribute the right side)

196 = 8x +16 (subtract 16 from both sides)

180 = 8x (divide both sides by 8)

x= 22.5 (is your answer, or C)

Step-by-step explanation:

3 0
3 years ago
The stream of water from a fountain follows a parabolic path. The stream reaches a maximum height of 7 feet, represented by a ve
xenn [34]

First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.

If we need the vertex to be at x=4, the equation will contain a (x-4)^2 term.

If we start with y=-(x-4)^2 we have a parabola, concave down, with vertex at x=4 and a maximum of 0.

So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be (4, 7)

We have

y = -(x-4)+7

Now we only have to fix the fact that this parabola doesn't land at (8,0), because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

y = a(x-4)^2+7

such that:

  • a
  • when we plug x=8, we have y=0

Plugging these values gets us

0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}

As you can see in the attached figure, the parabola we get satisfies all the requests.

3 0
3 years ago
Find the maximum volume of a rectangular box that is inscribed in a sphere of radius r.
zvonat [6]

Answer:

The maximum volume of a box inscribed in a sphere of radius r is a cube with volume \frac{8r^3}{3\sqrt{3}}.

Step-by-step explanation:

This is an optimization problem; that means that given the constraints on the problem, the answer must be found without assuming any shape of the box. That feat is made through the power of derivatives, in which all possible shapes are analyzed in its equation and the biggest -or smallest, given the case- answer is obtained. Now, 'common sense' tells us that the shape that can contain more volume is a symmetrical one, that is, a cube. In this case common sense is correct, and the assumption can save lots of calculations, however, mathematics has also shown us that sometimes 'common sense' fails us and the answer can be quite unintuitive. Therefore, it is best not to assume any shape, and that's how it will be solved here.

The first step of solving a mathematics problem (after understanding the problem, of course) is to write down the known information and variables, and make a picture if possible.

The equation of a sphere of radius r is x^2 + y^2 + z^2=r^2. Where x, y and z are the distances from the center of the sphere to any of its points in the border. Notice that this is the three-dimensional version of Pythagoras' theorem, and it means that a sphere is the collection of coordinates in which the equation holds for a given radius, and that you can treat this spherical problem in cartesian coordinates.

A box that touches its corners with the sphere with arbitrary side lenghts is drawn, and the distances from the center of the sphere -which is also the center of the box- to each cartesian axis are named x, y and z; then, the complete sides of the box are measured  2x,  2y and 2z. The volume V of any rectangular box is given by the product of its sides, that is, V=2x\cdot 2y\cdot 2z=8xyz.

Those are the two equations that bound the problem. The idea is to optimize V in terms of r, therefore the radius of the sphere must be introduced into the equation of the volumen of the box so that both variables are correlated. From the equation of the sphere one of the variables is isolated: z^2=r^2-x^2 - y^2\quad \Rightarrow z= \sqrt{r^2-x^2 - y^2}, so it can be replaced into the other: V=8xy\sqrt{r^2-x^2 - y^2}.

But there are still two coordinate variables that are not fixed and cannot be replaced or assumed. This is the point in which optimization kicks in through derivatives. In this case, we have a cube in which every cartesian coordinate is independent from each other, so a partial derivative is applied to each coordinate independently, and then the answer from both coordiantes is merged into a single equation and it will hopefully solve the problem.

The x coordinate is treated first: \frac{\partial V}{\partial x} =\frac{\partial 8xy\sqrt{r^2-x^2 - y^2}}{\partial x}, in a partial derivative the other variable(s) is(are) treated as constant(s), therefore the product rule is applied: \frac{\partial V}{\partial x} = 8y\sqrt{r^2-x^2 - y^2}  + 8xy \frac{(r^2-x^2 - y^2)^{-1/2}}{2} (-2x) (careful with the chain rule) and now the expression is reorganized so that a common denominator is found \frac{\partial V)}{\partial x} = \frac{8y(r^2-x^2 - y^2)}{\sqrt{r^2-x^2 - y^2}}  - \frac{8x^2y }{\sqrt{r^2-x^2 - y^2}} = \frac{8y(r^2-2x^2 - y^2)}{\sqrt{r^2-x^2 - y^2}}.

Since it cannot be simplified any further it is left like that and it is proceed to optimize the other variable, the coordinate y. The process is symmetrical due to the equivalence of both terms in the volume equation. Thus, \frac{\partial V}{\partial y} = \frac{8x(r^2-x^2 - 2y^2)}{\sqrt{r^2-x^2 - y^2}}.

The final step is to set both partial derivatives equal to zero, and that represents the value for x and y which sets the volume V to its maximum possible value.

\frac{\partial V}{\partial x} = \frac{8y(r^2-2x^2 - y^2)}{\sqrt{r^2-x^2 - y^2}} =0 \quad\Rightarrow r^2-2x^2 - y^2=0 so that the non-trivial answer is selected, then r^2=2x^2+ y^2. Similarly, from the other variable it is obtained that r^2=x^2+2 y^2. The last equation is multiplied by two and then it is substracted from the first, r^2=3 y^2\therefore y=\frac{r}{\sqrt{3}}. Similarly, x=\frac{r}{\sqrt{3}}.

Steps must be retraced to the volume equation V=8xy\sqrt{r^2-x^2 - y^2}=8\frac{r}{\sqrt{3}}\frac{r}{\sqrt{3}}\sqrt{r^2-\left(\frac{r}{\sqrt{3}}\right)^2 - \left(\frac{r}{\sqrt{3}}\right)^2}=8\frac{r^2}{3}\sqrt{r^2-\frac{r^2}{3} - \frac{r^2}{3}} =8\frac{r^2}{3}\sqrt{\frac{r^2}{3}}=8\frac{r^3}{3\sqrt{3}}.

6 0
3 years ago
4x - 3 &lt; 17. Solve for x.
Andru [333]

Answer:

c

Step-by-step explanation:

Subtract 17 by 3, and then you get 14, multiply 4 times 3 2/3 which gives you 14 with a fraction 2/3 so the answer is c

5 0
3 years ago
Other questions:
  • Creat an equation for a cubic function, in standard form, that has x- intercept given by the set {-3,1,7} and which passes throu
    6·1 answer
  • Why are diagrams that show how matter moves through organisms and the environment called cycles
    7·1 answer
  • P(B)=9/20 P(A and B)=9/100 P(A)=?
    7·1 answer
  • The marginal cost of drilling an oil well depends on the depth at which you are drilling; drilling becomes more expensive, per m
    8·1 answer
  • 4×2 0 2+ (3×2) find the value of the first expression
    15·1 answer
  • Andrew needs copies of a flyer for his band concert. The copy store prints 15 copies for $1.06. At that rate, how much will Andr
    9·2 answers
  • Maximize Q=xy^2, where x and y are positive numbers, such that x + y^2=10
    7·1 answer
  • What is the compound inequality?
    6·1 answer
  • Find the missing angles.
    8·1 answer
  • What is the square route of 48. Pls explain
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!