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kodGreya [7K]
3 years ago
11

MATH HELP

Mathematics
2 answers:
vampirchik [111]3 years ago
6 0
Collect like terms which will be
(8x+4)- (2y+4y-6)=
12x-2y-6
nordsb [41]3 years ago
5 0
I think that A. 12x+2y-6 is the answer, because 8+4 is 12 and -2+4 is 2 and there is nothing to combine with the 6.
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PLEASE HELP!<br><br> 7 x blank = 1
Tcecarenko [31]

Answer: 1/7

Step-by-step explanation:

7x=1

x=1/7

4 0
3 years ago
You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
Word problem:
Jlenok [28]

Answer:

Below.

Step-by-step explanation:

30 kg 500g + 28kg 700g

= 58kg + 1200g

= 59kg 200g.

Difference

= 30 kg 500g - 28kg 700g

= 2kg + 500 - 700

= 2kg - 200g

= 1kg 800g.

3 0
3 years ago
It is 4 : 12 p.M. 4:12 p.M.4, colon, 12, start text, space, p, point, m, point, end text Emma's mom will be home from work in 70
Vaselesa [24]

Answer:

40 Minutes.

Step-by-step explanation:

The current time = 4:12 p.M.

Emma's mom will be home from work in 70 minutes.

70 minutes = 1 hour 10 Minutes= 1: 10 Hours

\left\begin{array}{ccccc}&4&:&12 &p.m.\\+&1&:&10&\\--&--&--&--&--\\&5&:&22&p.m\end{array}\right

Therefore, Emma's Mom will get home by 5: 22 p.m.

Emma has gymnastics lessons at 6 : 00 p.M.

To determine how much time Emma will have between the time that her mom gets home from work and the beginning of gymnastics lessons, we simply subtract 5:22 from 6.

\left\begin{array}{ccccc}&6&:&00 &p.m.\\-&5&:&22&\\--&--&--&--&--\\&00&:&40&\end{array}\right

Emma  will have 40 Minutes.

5 0
3 years ago
What is the solution to the system of equations?
lord [1]

Answer:

We are sorry, but you do not have access to this service. Please contact your Organization Administrator for access.

5 0
3 years ago
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