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jeka57 [31]
2 years ago
15

Please help thank youuuuu

Mathematics
1 answer:
pentagon [3]2 years ago
5 0

Answer:

Y=3x-1

Step-by-step explanation:

Let x =1 then ,Y=(3×1)-1=2

Let x=2 then, Y=(3×2)-1=5

Let x=3 then Y=(3×3)-1=8

Let x=0 then Y=(3×0)-1=-1

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Which expression is equal to 4√32 • √2<br> A. 16<br> B. 4√2<br> C. 32<br> D. 16 √2
Georgia [21]

the is c.32$&$&#&#

Step-by-step explanation:

&&&&

4 0
2 years ago
Combine like terms: 8v-6j-10v+8j
diamong [38]
Just put them together. The subtraction sign is a negative sign. First step: 8v-10v= -2v Second Step: 8j-6j= 2j So your final answer would be: 2j-2v
5 0
3 years ago
Read 2 more answers
What were the dimensions of the slice defined as RSTU in Exercise 1?
antoniya [11.8K]

Answer:

how can I tell u the answer which out a pic

Step-by-step explanation:

7 0
3 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
−11 − 15 Group of answer choices -26 26 -4 4
kirill115 [55]
-26 is ur answer. hope this helps!
7 0
2 years ago
Read 2 more answers
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