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sertanlavr [38]
3 years ago
10

The set of integers from -3 to 3

Mathematics
1 answer:
sesenic [268]3 years ago
4 0

Answer:

-3, -2, -1, 0, 1, 2, 3

Step-by-step explanation:

I am pretty sure you are trying to ask this but don't mind if it's not. If it's not just ignore it.

-3 is the smallest, so you go see the integers above it that are equal or less than 3.

Integers are numbers that can be negative or positive, but cannot be a decimal, square root, X and more.

So then the answer should be

-3, -2, -1, 0, 1, 2, 3

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Monica has $4.75 on her
Aleksandr [31]

Answer:

6

4.75÷.75=6

3.25÷.50=6

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3 years ago
Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Which graph represents the arithmetic sequence 8 6 4 2 0
Nataliya [291]
Linear, because the points (1,8) (2,6) (3,4) etc are decreasing at a constant rate of -2.
7 0
3 years ago
Read 2 more answers
Mr. Santiago has a flight from New York to Paris that covers a distance of 3,636 miles. If the plane travels at 520 miles per ho
sertanlavr [38]
Time = distance / speed

time = 3636 / 520 = 6.99 hrs rounds to 7 hrs
5 0
3 years ago
Quadrilaterals Q and P are similar. What is the scale factor of the dilation that takes Q to P
aalyn [17]

Answer:

0.8

Step-by-step explanation:

The scale factor that takes Q to P

Here, we want to go from Q to P

To get this, we simply divide what we have in P by what we had in Q

Hence, what we do here is;

2/2.5 or 4/5 = 0.8

8 0
3 years ago
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