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1 year ago

What is the mode of the data represented in this line plot? Enter your answer in the box.

Mathematics

1 answer:

Semenov [28]1 year ago

5 0

Answer:

Offmind's Step-by-step explanation:

The Mode of a data set (<em>line plot in this case</em>) is the number which occurs most often. The line plot here shows the most x's on the number 2 than any other number so the mode is in fact, 2.

Bonus Fact: In another case, if there had been two numbers with the same amount of x's then those would both be considered the mode!

If you found this answer helpful please consider marking it Brainliest

Thanks!

-<em>Offmind</em>

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the average person takes about 30,000 breaths per day. express this number as a single digit integer times a power of 10

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Answer:

3 * 10^4

Step-by-step explanation:

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3 years ago

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In Exercises 26 and 27 write an equation of the line with the given slope and y-intercept.

Neko [114]

26. y= -7/3+ 0 or just y= -7/3

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2 years ago

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dlinn [17]

Answer:

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Step-by-step explanation:

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2 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

2 years ago

Answer the photo please

alexandr402 [8]

Answer:

66.666666666667% error

Step-by-step explanation:

Percent Error = Vobserved - Vtrue / Vtrue

= 9 - 27 / 27

= -18/27

= -66.666666666667%

= 66.666666666667% error

I hope this helps!

7 0

3 years ago