With rational coefficients (a, b and c), if one zero is rational, that means the discriminant is rational. We can conclude that the other is also rational.
Answer: [B]: "contains one point" .
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Explanation:
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Given:
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x + y = 6 ;
x - y = 0 ;
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To solve for "x" ;
Consider the first equation:
x + y = 6 ;
subtract "y" from each side of the equation ; to isolate "x" on one side of the equation; and to solve for "x" ;
x + y - y = 6 - y ;
x = 6 - y ;
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Take the second equation:
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x - y = 0 ;
Solve for "x" ;
Add "y" to EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
x - y + y = 0 + y ;
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x = y
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x = 6 - y
Substitute "x" for "y" ;
x = 6 - x ;
Add "x" to Each side of the equation:
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x + x = 6 - x + x ;
2x = 6 ;
Now, divide EACH SIDE of the equation by "2" ; to isolate "x" on one side of the equation; and to solve for "x" ;
2x/2 = 6/2 ;
x = 3 .
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Now, since "x = 3" ; substitute "3" for "x" in both original equations; to see if we get the same value for "y" ;
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x + y = 6 ;
x - y = 0
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Start with the first equation:
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x + y = 6 ;
3 + y = 6 ;
Subtract "3" from each side of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
3 + y - 3 = 6 - 3 ;
y = 3 .
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Now, continue with the second equation; {Substitute "3" for "x" to see the value we get for "y"} ;
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The second equation given is:
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x - y = 0 ;
Substitute "3" for "x" to solve for "y" ;
3 - y = 0 ;
Subtract "3" from EACH side of the equation:
3 - y - 3 = 0 - 3 ;
-1y = -3 ;
Divide EACH side of the equation by "-1" ; to isolate "y" on one side of the equation; and to solve for "y" ;
-1y/-1 = -3/-1 ;
y = 3 .
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So, for both equations, we have one value: x = 3, y = 3; or: write as:
"(3, 3)" ; { which is: "one single point" ; which is: Answer choice: [B] } .
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Your Daily Sale Goal should be $611.61 to achieve the $18.65k monthly goal
Answer:
127.23
Step-by-step explanation:
Equation
pi/8×18^2=127.2345025 rounded 127.23