Answer:What is the 11th term of this geometric sequence 5, 20, 80, 320? In the present GP, a = 5 and r = 20/5 = 4. So the 11th term of the GP = ar^10 = 5*4^10 = 5242880.
Step-by-step explanation:
The square root of 34 is just sqrt(34), or if you're looking for a rounded decimal answer, about 5.83. The square root of -4/11:
The square root of 34 is an irrational number. The square root of -4/11 is an imaginary number, or nonreal complex number.
Answer:
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Answer:
200.96 = area of Shaded portions.
Step-by-step explanation:
Area of the 2 stars.
I don't know if you can see this or not, but the 4 quarter circles surrounding the star is found by subtracting a full small square surrounding the star
Area of 1 star = 4 * (1/4) pi * r^2
Area of 1 star = 3.14 * 4^2
Area of 1 star = 50.24
Area of both stars = 100.48
Area of the 4 semicircles at each end
The 2 semicircles at one end figure = 1 circle
The two circles gives the total area of the 4 semicircles.
Area 1 circle = pr * r^2
Area 1 circle = 3.14 * (8/2)^2
Area 1 circle = 50.24
There are 2 such circles = 100.48
Total area of both results
Total Area = 100.48 + 100.48
Total Area = 200.96
Answer:
Well.... your problem isnt even there lol