All the answers are gotten using the lcm method
1.8/11
2.3/23
3.1/2
4.13/15
5.8/11
6.49/30
7.22/3
8.19/60
1.8/11
2.3/23
3.1/2
4.13/15
5.8/11
6.49/30
7.22/3
8.19/60
Rewrite the expression in terms of ln 4 and ln 5. ln(400)
1 answer:
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Answer: 1.25
Step-by-step explanation:
Given: A college-entrance exam is designed so that scores are normally distributed with a mean = 500 and a standard deviation
= 100.
A z-score measures how many standard deviations a given measurement deviates from the mean.
Let Y be a random variable that denotes the scores in the exam.
Formula for z-score =
Z-score =
⇒ Z-score =
⇒Z-score =1.25
Therefore , the required z-score = 1.25