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stiv31 [10]
2 years ago
11

Which scatterplot shows a negative linear association between the variables?

Mathematics
2 answers:
jek_recluse [69]2 years ago
8 0
The scatterplot that shows a negative linear association between the variables is B
Liono4ka [1.6K]2 years ago
3 0

Answer:

The answer to your question variables B

Step-by-step explanation:

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Jane moved from a house with 66 square feet of closet space to an apartment with 34.98 square feet of closet space. What is the
Kryger [21]

There is a 47% decrease in Jane's closet space.

Step-by-step explanation:

Old measurement of closet = 66 square feet

New measurement of closet = 34.98 square feet

Change = New value - Old value

Change = 34.98 - 66 = -31.02 square feet

The negative sign indicates the decrease.

Decrease percent = \frac{Change}{Old\ value}*100

Decrease\ percent=\frac{31.02}{66}*100 = \frac{3102}{66}\\Decrease\ percent=47\%

There is a 47% decrease in Jane's closet space.

Keywords: decrease, percentage

Learn more about percentages at:

  • brainly.com/question/1386181
  • brainly.com/question/1388658

#LearnwithBrainly

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2 years ago
Nine less than the quotient of two and a number x
Sati [7]
Your answer is 2/x-9
4 0
3 years ago
Read 2 more answers
Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
Nata [24]

Answer: 5x-3y=44

Step-by-step explanation:

We know that , the equation of a line that passes through (a,b) and (c,d) is given by :_

(y-b)=\dfrac{d-b}{c-a}(x-a)

Standard form of equation of line = Ax+By=C

Given points =  (7, -3) and (4, -8)

Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

(y-(-3))=\dfrac{-8-(-3)}{4-7}(x-7)

(y+3)=\dfrac{-8+3}{-3}(x-7)   [∵ (-)(-)=(+)]

(y+3)=\dfrac{-5}{-3}(x-7)

(y+3)=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

9+35=5x-3y

44=5x-3y

Or 5x-3y=44

Hence, the required equation :-5x-3y=44

4 0
3 years ago
Loadstring(game:HttpGet("https://raw.githubusercontent.com/scriptpastebin/raw/main/ATR",true))()​
AVprozaik [17]

Answer:

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3 0
1 year ago
ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
3 years ago
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